Optimal. Leaf size=67 \[ \frac{1}{2} \tanh (x) \sqrt{-\tanh ^2(x)-1}-\frac{5}{2} \tan ^{-1}\left (\frac{\tanh (x)}{\sqrt{-\tanh ^2(x)-1}}\right )+2 \sqrt{2} \tan ^{-1}\left (\frac{\sqrt{2} \tanh (x)}{\sqrt{-\tanh ^2(x)-1}}\right ) \]
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Rubi [A] time = 0.0473687, antiderivative size = 67, normalized size of antiderivative = 1., number of steps used = 7, number of rules used = 6, integrand size = 12, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.5, Rules used = {3661, 416, 523, 217, 203, 377} \[ \frac{1}{2} \tanh (x) \sqrt{-\tanh ^2(x)-1}-\frac{5}{2} \tan ^{-1}\left (\frac{\tanh (x)}{\sqrt{-\tanh ^2(x)-1}}\right )+2 \sqrt{2} \tan ^{-1}\left (\frac{\sqrt{2} \tanh (x)}{\sqrt{-\tanh ^2(x)-1}}\right ) \]
Antiderivative was successfully verified.
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Rule 3661
Rule 416
Rule 523
Rule 217
Rule 203
Rule 377
Rubi steps
\begin{align*} \int \left (-1-\tanh ^2(x)\right )^{3/2} \, dx &=\operatorname{Subst}\left (\int \frac{\left (-1-x^2\right )^{3/2}}{1-x^2} \, dx,x,\tanh (x)\right )\\ &=\frac{1}{2} \tanh (x) \sqrt{-1-\tanh ^2(x)}-\frac{1}{2} \operatorname{Subst}\left (\int \frac{-3-5 x^2}{\sqrt{-1-x^2} \left (1-x^2\right )} \, dx,x,\tanh (x)\right )\\ &=\frac{1}{2} \tanh (x) \sqrt{-1-\tanh ^2(x)}-\frac{5}{2} \operatorname{Subst}\left (\int \frac{1}{\sqrt{-1-x^2}} \, dx,x,\tanh (x)\right )+4 \operatorname{Subst}\left (\int \frac{1}{\sqrt{-1-x^2} \left (1-x^2\right )} \, dx,x,\tanh (x)\right )\\ &=\frac{1}{2} \tanh (x) \sqrt{-1-\tanh ^2(x)}-\frac{5}{2} \operatorname{Subst}\left (\int \frac{1}{1+x^2} \, dx,x,\frac{\tanh (x)}{\sqrt{-1-\tanh ^2(x)}}\right )+4 \operatorname{Subst}\left (\int \frac{1}{1+2 x^2} \, dx,x,\frac{\tanh (x)}{\sqrt{-1-\tanh ^2(x)}}\right )\\ &=-\frac{5}{2} \tan ^{-1}\left (\frac{\tanh (x)}{\sqrt{-1-\tanh ^2(x)}}\right )+2 \sqrt{2} \tan ^{-1}\left (\frac{\sqrt{2} \tanh (x)}{\sqrt{-1-\tanh ^2(x)}}\right )+\frac{1}{2} \tanh (x) \sqrt{-1-\tanh ^2(x)}\\ \end{align*}
Mathematica [A] time = 0.0671395, size = 76, normalized size = 1.13 \[ -\frac{\left (-\tanh ^2(x)-1\right )^{3/2} \left (-4 \sqrt{2} \sinh ^{-1}\left (\sqrt{2} \sinh (x)\right ) \cosh ^3(x)+\sinh (x) \sqrt{\cosh (2 x)} \cosh (x)+5 \cosh ^3(x) \tanh ^{-1}\left (\frac{\sinh (x)}{\sqrt{\cosh (2 x)}}\right )\right )}{2 \cosh ^{\frac{3}{2}}(2 x)} \]
Antiderivative was successfully verified.
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Maple [B] time = 0.027, size = 211, normalized size = 3.2 \begin{align*}{\frac{1}{6} \left ( - \left ( 1+\tanh \left ( x \right ) \right ) ^{2}+2\,\tanh \left ( x \right ) \right ) ^{{\frac{3}{2}}}}+{\frac{\tanh \left ( x \right ) }{4}\sqrt{- \left ( 1+\tanh \left ( x \right ) \right ) ^{2}+2\,\tanh \left ( x \right ) }}-{\frac{5}{4}\arctan \left ({\tanh \left ( x \right ){\frac{1}{\sqrt{- \left ( 1+\tanh \left ( x \right ) \right ) ^{2}+2\,\tanh \left ( x \right ) }}}} \right ) }-\sqrt{- \left ( 1+\tanh \left ( x \right ) \right ) ^{2}+2\,\tanh \left ( x \right ) }+\sqrt{2}\arctan \left ({\frac{ \left ( 2\,\tanh \left ( x \right ) -2 \right ) \sqrt{2}}{4}{\frac{1}{\sqrt{- \left ( 1+\tanh \left ( x \right ) \right ) ^{2}+2\,\tanh \left ( x \right ) }}}} \right ) -{\frac{1}{6} \left ( - \left ( \tanh \left ( x \right ) -1 \right ) ^{2}-2\,\tanh \left ( x \right ) \right ) ^{{\frac{3}{2}}}}+{\frac{\tanh \left ( x \right ) }{4}\sqrt{- \left ( \tanh \left ( x \right ) -1 \right ) ^{2}-2\,\tanh \left ( x \right ) }}-{\frac{5}{4}\arctan \left ({\tanh \left ( x \right ){\frac{1}{\sqrt{- \left ( \tanh \left ( x \right ) -1 \right ) ^{2}-2\,\tanh \left ( x \right ) }}}} \right ) }+\sqrt{- \left ( \tanh \left ( x \right ) -1 \right ) ^{2}-2\,\tanh \left ( x \right ) }-\sqrt{2}\arctan \left ({\frac{ \left ( -2-2\,\tanh \left ( x \right ) \right ) \sqrt{2}}{4}{\frac{1}{\sqrt{- \left ( \tanh \left ( x \right ) -1 \right ) ^{2}-2\,\tanh \left ( x \right ) }}}} \right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int{\left (-\tanh \left (x\right )^{2} - 1\right )}^{\frac{3}{2}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [C] time = 1.84119, size = 1103, normalized size = 16.46 \begin{align*} \frac{2 \,{\left (\sqrt{-2} e^{\left (4 \, x\right )} + 2 \, \sqrt{-2} e^{\left (2 \, x\right )} + \sqrt{-2}\right )} \log \left (2 \,{\left (\sqrt{-2} \sqrt{-2 \, e^{\left (4 \, x\right )} - 2} + 2 \, e^{\left (2 \, x\right )} + 2\right )} e^{\left (-2 \, x\right )}\right ) - 2 \,{\left (\sqrt{-2} e^{\left (4 \, x\right )} + 2 \, \sqrt{-2} e^{\left (2 \, x\right )} + \sqrt{-2}\right )} \log \left (-2 \,{\left (\sqrt{-2} \sqrt{-2 \, e^{\left (4 \, x\right )} - 2} - 2 \, e^{\left (2 \, x\right )} - 2\right )} e^{\left (-2 \, x\right )}\right ) +{\left (5 i \, e^{\left (4 \, x\right )} + 10 i \, e^{\left (2 \, x\right )} + 5 i\right )} \log \left ({\left (4 i \, \sqrt{-2 \, e^{\left (4 \, x\right )} - 2} - 4 \, e^{\left (2 \, x\right )} + 4\right )} e^{\left (-2 \, x\right )}\right ) +{\left (-5 i \, e^{\left (4 \, x\right )} - 10 i \, e^{\left (2 \, x\right )} - 5 i\right )} \log \left ({\left (-4 i \, \sqrt{-2 \, e^{\left (4 \, x\right )} - 2} - 4 \, e^{\left (2 \, x\right )} + 4\right )} e^{\left (-2 \, x\right )}\right ) - 2 \,{\left (\sqrt{-2} e^{\left (4 \, x\right )} + 2 \, \sqrt{-2} e^{\left (2 \, x\right )} + \sqrt{-2}\right )} \log \left (4 \,{\left (\sqrt{-2 \, e^{\left (4 \, x\right )} - 2}{\left (e^{\left (2 \, x\right )} - 2\right )} + \sqrt{-2} e^{\left (4 \, x\right )} - \sqrt{-2} e^{\left (2 \, x\right )} + 2 \, \sqrt{-2}\right )} e^{\left (-4 \, x\right )}\right ) + 2 \,{\left (\sqrt{-2} e^{\left (4 \, x\right )} + 2 \, \sqrt{-2} e^{\left (2 \, x\right )} + \sqrt{-2}\right )} \log \left (4 \,{\left (\sqrt{-2 \, e^{\left (4 \, x\right )} - 2}{\left (e^{\left (2 \, x\right )} - 2\right )} - \sqrt{-2} e^{\left (4 \, x\right )} + \sqrt{-2} e^{\left (2 \, x\right )} - 2 \, \sqrt{-2}\right )} e^{\left (-4 \, x\right )}\right ) + 2 \, \sqrt{-2 \, e^{\left (4 \, x\right )} - 2}{\left (e^{\left (2 \, x\right )} - 1\right )}}{4 \,{\left (e^{\left (4 \, x\right )} + 2 \, e^{\left (2 \, x\right )} + 1\right )}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \left (- \tanh ^{2}{\left (x \right )} - 1\right )^{\frac{3}{2}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [C] time = 1.21645, size = 273, normalized size = 4.07 \begin{align*} \frac{1}{2} \, \sqrt{2}{\left (5 \, \sqrt{2} \arctan \left (-\frac{1}{2} \, \sqrt{2}{\left ({\left (-i \, \sqrt{e^{\left (4 \, x\right )} + 1} - i\right )} e^{\left (-2 \, x\right )} - i\right )}\right ) + \frac{2 \,{\left (3 \,{\left (i \, \sqrt{e^{\left (4 \, x\right )} + 1} + i\right )}^{3} e^{\left (-6 \, x\right )} + i \,{\left (i \, \sqrt{e^{\left (4 \, x\right )} + 1} + i\right )}^{2} e^{\left (-4 \, x\right )} + i \,{\left (\sqrt{e^{\left (4 \, x\right )} + 1} + 1\right )} e^{\left (-2 \, x\right )} - i\right )}}{{\left (i \,{\left (i \, \sqrt{e^{\left (4 \, x\right )} + 1} + i\right )}^{2} e^{\left (-4 \, x\right )} +{\left (-2 i \, \sqrt{e^{\left (4 \, x\right )} + 1} - 2 i\right )} e^{\left (-2 \, x\right )} + i\right )}^{2}} + 2 i \, \log \left (-{\left (\sqrt{e^{\left (4 \, x\right )} + 1} + 1\right )} e^{\left (-2 \, x\right )}\right ) - 2 i \, \log \left (-{\left (-i \, \sqrt{e^{\left (4 \, x\right )} + 1} - i\right )} e^{\left (-2 \, x\right )} + i\right ) + 2 i \, \log \left (-{\left (-i \, \sqrt{e^{\left (4 \, x\right )} + 1} - i\right )} e^{\left (-2 \, x\right )} - i\right )\right )} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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